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Nuclear Research with Low Energy Accelerators by Jerry B. Marion

By Jerry B. Marion

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The fact is that we do not have an accurate quantitative theory for the energy loss and scattering process. , Ref. 28) has provided us with a qualitative understanding of the general features of the process; that is, 52 LOW ENERGY NUCLEAR RESEARCH the dependence on ion velocity of the energy loss and scattering of an ideal ion traversing an ideal stopping material. There are two practical difficulties. 5%) and second, at higher ion velocities (v/c — 1-6%), fluctuations with Ζ of the moving ion about the predicted magnitude of the energy loss of up to 20% are observed experi­ mentally,^ Recently, several f o r m u l a t i o n s 2 2' 2 4' 2 7' 29 of the DSAM have been presented which go considerably further than previous work in utilizing our knowledge of the energy loss and scattering process.

1 8 + 0 . 01). The l i n e a r p o l a r i z a t i o n s of γι and γ 2 w e r e m e a s u r e d w i t h the C o m p t o n p o l a r i m e t e r setup shown s c h e m a t i c a l l y in F i g . 5. T h e s c a t t e r e r , l o c a t e d v e r t i c a l l y a b o v e the t a r g e t , i s a 2 in. χ 2 in. N a l ( T l ) c r y s t a l . The analyzing d e t e c t o r s , A and B , o r i e n t e d a s shown at φ = 9 0 ° and φ = 0 ° , a r e 5 i n . χ 5 in. Nal(Tl) c r y s t a l s . Standard e l e c t r o n i c techniques are u s e d to obtain s u m s p e c t r a f r o m the two s c a t t e r i n g c r y s t a l a n a l y z i n g c r y s t a l c o m b i n a t i o n s , w h i c h a r e r e c o r d e d in s e p a ­ r a t e m e m o r y s u b g r o u p s of a m u l t i c h a n n e l a n a l y z e r .

0 2 M e V l e v e l s . T C data (not shown) on the R e s . - β . 0 2 - > 0 . 6 8 0 c a s c a d e c o n f i r m the r e s o n a n c e spin, but a g r e e with e i t h e r J(3. 02) = 1 o r 2. T h e s e T C data, c o m b i n e d with A D data on R e s . - ^ O , f i x the p o p u l a t i o n p a r a m e t e r s of the r e s o n a n c e a s P ( 0 ) = 0. 51 + 0 . 0 2 and P ( l ) = 0 . 4 9 + 0 . 0 2 . This 31 GALE I. HARRIS r e s u l t c o r r e s p o n d s to s o l u t i o n s x 2 = 0 , 21 or 2 3 . 2 f o r the r a t i o of P 3 / 2 t o P i / 2 f o r r ni a° nt T h e l a t t e r v a l u e i s probablyc o r r e c t f o r this r e s o n a n c e s i n c e it i s e x p e c t e d that the m a i n s t r e n g t h of the 2 p i / 2 c o n f i g u r a t i o n should l i e c o n s i d e r a b l y h i g h e r in e x c i t a t i o n e n e r g y .

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